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lys-0071 [83]
3 years ago
14

What is the percent of 1.6 hours to 0.95 hour

Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0
1.6*100/0.95=168%     1.6 to 0.95
0.95*100/1.6=59%       0.95 to 1.6
Akimi4 [234]3 years ago
4 0

Answer:

168.4%  of 1.6 hours to 0.95 hour.

Step-by-step explanation:

Given : 1.6 hours to 0.95 hour.

To find : what is the percent.

Solution : We have given

1.6 hours to 0.95 hour.

Percentage  = \frac{1.6}{0.95}*100.xzs

Percentage  = 1.684 * 100

Percentage=  168.4%

Therefore, 168.4%  of 1.6 hours to 0.95 hour.

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antiseptic1488 [7]

Answer:

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Step-by-step explanation:

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Read 2 more answers
Find the slope of the line through each pair of points.<br> (-2, -12) and (-18, -12)
Jobisdone [24]

Answer:

0/16

Step-by-step explanation:

you use the equation y2-y1/x2-x1 so -12-(-12) which is 0 then do -18-(-2)=-16 so the slope is 0/-16

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3 years ago
Alan buys a basket of apples on sale for $7 before tax. The sales tax is 12.5%. What is the
shtirl [24]
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5 0
2 years ago
For each value of y, determine whether it is a solution to -2y+75-5.<br> Is it a solution?
ser-zykov [4K]

Answer:

• No

• Yes

• Yes

• No

Step-by-step explanation:

To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.

-2y +7≤ -5

Subtract 7 on both sides:

-2y≤ -5 -7

-2y≤ -12

Divide by -2 on both sides:

y≥ 6

This means that the solution can be 6 or greater than 6.

-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.

_______

Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.

Here's an example to check if -10 is a solution.

-2y +7≤ -5

When y= -10,

-2y +7

= -2(-10) +7

= 20 +7

= 27

Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.

3 0
2 years ago
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