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2 years ago

Simple interest $1600.00 at 6% for 180 days

Mathematics

1 answer:

ikadub [295]2 years ago

7 0

Answer:

Interest = $47.34

Step-by-step explanation:

Formula:-

Simple interest I = PNR/100

P - Principle amount

N - number of years

R - Rate of interest

It is given that

P = $ 1600

R = 6%

Number of days = 180 days

To find the simple interest for 1 year(365 days) 

I = PNR/100

= (1600 * 1 * 6)/100 = $96

To find the interest for 180 days 

For 365 day I = $96

For 180 days I = (180/365) * 96

I = $47.34

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If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

Factor each polynomial. Look for a GCF first

weeeeeb [17]

Answer:

20. $x\left(x-6\right)\left(x+8\right)$

22. $2\left(x+1\right)\left(x+4\right)$

24. $5m\left(m-1\right)\left(m+7\right)$

Step-by-step explanation:

20. $x^3+2x^{2} -48x$

The GCF is x, so you group it out of the equation first.

$x(x^{2} +2x-48)$

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

$?+?=2\\?*?=-48$

The two numbers would be -6 and 8. You then differentiate the squares.

$x\left(x-6\right)\left(x+8\right)$

22. $2x^{2} +10x+8$

The GCF is 2, so you must group it out.

$2(x^{2} +5x+4)$

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

$?+?=5\\?*?=4$

The two numbers would be 1 and 4. Finally, differentiate the squares.

$2\left(x+1\right)\left(x+4\right)$

24. $5m^{3} +30m^2-35m$

The GCF is 5m, so you must group it out.

$5m(m^2+6m-7)$

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

$?+?=6\\?*?=-7$

The two numbers would be -1 and 7. Finally, differentiate the squares.

$5m\left(m-1\right)\left(m+7\right)$

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2 years ago

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Step-by-step explanation:

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