Solve for x
Logx-log(x+13)=1
Step by step explanation please
1 answer:
Answer:
Step-by-step explanation:
Applying logarithm rule
Log A - Log B= Log(A/B). Division rule
Now, Logx-log(x+13)=1
Log(x/(x+13))=1
Assume that the log is a natural log whose base is 10.
Then apply logarithm law
Log10 base 10=1
Comparing this to Log(x/(x+13))=1
This implies that
x/(x+13)=10
x=10(x+13)
x=10x+130
x-10x=130
-9x=130
x=130/-9
x=-14.444
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