Answer:
The answer is d
Step-by-step explanation:
I graphed it
-b/2a to get the vertex
3x^2-12+9
-(-12)/(2)(3)=2
plug in 2 to the function
12-24+9=-3 which is the y value on the graph
(2,-3) is the vertex
d<em>y</em>/d<em>x</em> = 4 + √(<em>y</em> - 4<em>x</em> + 6)
Make a substitution of <em>v(x)</em> = <em>y(x)</em> - 4<em>x</em> + 6, so that d<em>v</em>/d<em>x</em> = d<em>y</em>/d<em>x</em> - 4. Then the DE becomes
d<em>v</em>/d<em>x</em> + 4 = 4 + √<em>v</em>
d<em>v</em>/d<em>x</em> = √<em>v</em>
which is separable as
d<em>v</em>/√<em>v</em> = d<em>x</em>
Integrating both sides gives
2√<em>v</em> = <em>x</em> + <em>C</em>
Get the solution back in terms of <em>y</em> :
2√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em> + <em>C</em>
You can go on to solve for <em>y</em> explicitly if you want.
√(<em>y</em> - 4<em>x</em> + 6) = <em>x</em>/2 + <em>C</em>
<em>y</em> - 4<em>x</em> + 6 = (<em>x</em>/2 + <em>C </em>)²
<em>y</em> = 4<em>x</em> - 6 + (<em>x</em>/2 + <em>C </em>)²
Im sorry i dont know the question but i do know that god loves u
Step-by-step explanation:
since KLJ is a parallelogram, it can be split into 2 congruent triangles, as seen above. The angles remain the same, so we know angle KJL is also 25 degrees. Using the triangle angle sum theorem (all sides of a triangle add up to 180 degrees), we can determine the missing angle measure is 25 degrees. It would have been nice if the question told us JKLM was also a rhombus.
