Rates like $ per channel is a slope, "m". The added fee is a constant so it's the intercept "b".
y = mx + b
So for the first problem (9)
(a)
y = total cost in dollars
x = number of premium channels
y = 16x + 44
(b) when x = 3 channels
y = 16(3) + 44
y = 92 $
the second problem (10)
(a) every 4 years the tree grows by 12-9=3 ft
So the unit rate or slope will be 3 ft per 4 yrs, (3/4). You can see this also by solving for slope "m" using the given points (4,9) and (8,12).
x = number of years
y = height of tree in ft
y = (3/4)x + b
use one of the points to find the y-intercept "b".
9 = (3/4)(4) + b
9 = 3 + b
9 - 3 = b
6 = b
y = (3/4)x + 6
(b) when x = 16
y = (3/4)(16) + 6
y = 12 + 6
y = 18 ft
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
6. (A/pi = r^2)
7. [(P - 2l)/2 = w]
8. [C/(2pi)= r]
9. (2A/h = b)
10. (E/c^2 = m)
