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3 years ago

5

Solve each equation1) v- 10=-9

1 answer:

Luba_88 [7]3 years ago

6 0

Answer:

$v=1$

Step-by-step explanation:

$v-10=-9\\\\ +10 +10\\\\v=1$

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An electrician uses 46 3/4 feet of push-back wire from a 200-foot roll. How many feet of wire are left on the roll?

kolbaska11 [484]

Answer:

<u>153 1/4 feet</u>

Step-by-step explanation:

Remaining

200 - 46 3/4
<u>153 1/4 feet</u>

4 0

2 years ago

Hi i just like kinda forgot what that line above the two numbers in 2.21 mean. Can you help me?

yan [13]

Answer:

It means .21 never ends like 2.2121212121.....

8 0

4 years ago

Read 2 more answers

I need help figuring out what I did wrong

rewona [7]

Answer:

D

Step-by-step explanation:

Using the addition formula for sine

sin(a + b) = sinacosb + cosasinb

and the exact values

sin( $\frac{\pi }{4}$ ) = cos( $\frac{\pi }{4}$ ) = $\frac{\sqrt{2} }{2}$ , cos( $\frac{\pi }{6}$ ) = $\frac{\sqrt{3} }{2}$ , sin( $\frac{\pi }{6}$ ) = $\frac{1}{2}$

Note that $\frac{5\pi }{12}$ = $\frac{\pi }{4}$ + $\frac{\pi }{6}$ , thus

sin( $\frac{5\pi }{12}$ )

= sin( $\frac{\pi }{4}$ + $\frac{\pi }{6}$ )

= sin( $\frac{\pi }{4}$ )cos( $\frac{\pi }{6}$ ) + cos( $\frac{\pi }{4}$ )sin( $\frac{\pi }{6}$ )

= ( $\frac{\sqrt{2} }{2}$ × $\frac{\sqrt{3} }{2}$ ) + ( $\frac{\sqrt{2} }{2}$ × $\frac{1}{2}$ )

= $\frac{\sqrt{6} }{4}$ + $\frac{\sqrt{2} }{4}$

= $\frac{\sqrt{6}+\sqrt{2} }{4}$ → D

4 0

3 years ago

Read 2 more answers

How do you graph y=-x-2?

Dafna1 [17]

Answer:

Ok i'm going to try to explain this

Step-by-step explanation:

So the X Intercept is -2, and the Y intercept is -2 aswell.

Every 1x, it does down by one. Here is a graph.

5 0

3 years ago

he Sunny Days Apartment building has a cylindrical, above ground pool in the yard. The radius of the pool is 1.5 times its heigh

tatiyna

Answer:

5.54 feet.

Step-by-step explanation:

Let h be the height of the pool and r be the radius of the pool.

We have been given that volume of cylindrical pool in Sunny Days Apartment building is 1200 cubic feet.

We have been given that the radius of the pool is 1.5 times its height. We can represent this information in an equation as:

$r=1.5*h...(1)$

$\text{Volume of cylinder}=\pi r^2h$

Substituting equation (1) in volume formula we will get,

$\text{Volume of cylindrical pool}=\pi (1.5h)^2*h$

Substituting the given volume of pool in formula we will get,

$1200=\pi (1.5h)^2*h$

$1200=\pi*2.25*h^2*h$

$1200=\pi*2.25*h^3$

Let us divide both sides of our equation by 2.25 pi.

$\frac{1200}{2.25\pi}=\frac{\pi*2.25*h^3}{2.25\pi}$

$169.7652726=h^3$

Let us take cube root of both sides of our equation.

$\sqrt[3]{169.7652726}=h$

$5.537=h$

$h=5.537\approx 5.54$

Therefore, the height of the pool is approximately 5.54 feet.

8 0

4 years ago