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SashulF [63]
3 years ago
11

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

separated list. If an answer does not exist, enter DNE.) f(x) = x , [0, 25]
Mathematics
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

c is all the points in the open interval (0,25)

Step-by-step explanation:

Here given is a function

f(x) =x, which is continuous  in the interval [0,25] and differentiable in (0,25)

Mean value theorem says there exists at least one c in the interval (0,25) such that

f'(c) = \frac{f(25)-f(0)}{25-0}

We have

f(25)=25 and f(0) = 0\\f'(c) = 1

For the given function

f'(x) =1

Hence we have c equals all the points in the open interval (0,25)

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a) z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250  

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If we compare the p value and the significance level given we see that p_v we have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Data given and notation

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z would represent the statistic (variable of interest)

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Part a

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Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.684 -0.58}{\sqrt{\frac{0.58(1-0.58)}{114}}}=2.250  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z>2.250)=0.0244  

If we compare the p value and the significance level given we see that p_v we have enough evidence to reject the null hypothesis at 5% of significance.

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