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SashulF [63]
4 years ago
11

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

separated list. If an answer does not exist, enter DNE.) f(x) = x , [0, 25]
Mathematics
1 answer:
coldgirl [10]4 years ago
7 0

Answer:

c is all the points in the open interval (0,25)

Step-by-step explanation:

Here given is a function

f(x) =x, which is continuous  in the interval [0,25] and differentiable in (0,25)

Mean value theorem says there exists at least one c in the interval (0,25) such that

f'(c) = \frac{f(25)-f(0)}{25-0}

We have

f(25)=25 and f(0) = 0\\f'(c) = 1

For the given function

f'(x) =1

Hence we have c equals all the points in the open interval (0,25)

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Need help again. Please explain your answer.
Elis [28]

4y + 3 ≤ y + 6

4y + 3 - 3 ≤ y + 6 - 3

4y ≤ y + 3

4y - y ≤ y - y + 3

3y ≤ 3

3y/3 ≤ 3/3

y ≤ 1

So any value of y less than or equal to 1 (so 1 is included in the solution set) satisfies the inequality. C is the correct answer.

5 0
3 years ago
Talia used 1/3 of a piece of wood for the base of her project 1/4 of the piece of wood for the vertical support and the rest for
Veseljchak [2.6K]

Answer:

The fraction of wood used for horizontal support is \frac{5}{12}.

Step-by-step explanation:

Assume that the total piece of wood is of length 1.

It is provided that Talia used \frac{1}{3} of the piece of wood for the base of he project.

She use \frac{1}{4} of the piece of wood for the for the vertical support.

The remaining wood she used for horizontal support.

The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.

Compute the amount of wood used for horizontal support as follows:

Horizontal\ support=1-Base\ of\ project-Vertical\ support\\= 1 - \frac{1}{3}-\frac{1}{4}\\  =\frac{12-4-3}{12} \\=\frac{5}{12}

Thus, the fraction of wood used for horizontal support is \frac{5}{12}.

3 0
3 years ago
A line passes through the points (2,-4) and (6,10). What is the equation of the line?
deff fn [24]

Answer:

y = \frac{7}{2} x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (6, 10)

m = \frac{10+4}{6-2} = \frac{14}{4} = \frac{7}{2} , thus

y = \frac{7}{2} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, - 4) , then

- 4 = 7 + c ⇒ c = - 4 - 7 = - 11

y = \frac{7}{2} x - 11 ← equation of line

7 0
3 years ago
Assignment: Translating Functions Investigation
Leto [7]

Answer:

Part A)

1) The graph in the attached figure N 1

2) The coordinate rule is (x,y) -----> (x,y+10)

3) The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

1) The graph in the attached figure N2

2) The coordinate rule is (x,y) -----> (x-10,y)

3) The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1) In each translation, the slope is the same (m=5) are parallel lines

2) The vertical translation would be up 40 units

Step-by-step explanation:

we have

f(x)=5x+50

where

f(x) --> represents Jeremy's account balance

x ---> the time in years

Part A)

The translation of the function is up 10 units.

The rule of the translation is equal to

(x,y) -----> (x,y+10)

so

The new function will be

f(x)=5x+50+10

f(x)=5x+60

The graph in the attached figure N 1

The translation of the function up 10 units means that the initial deposit is $60 instead of $50

Part B)

The translation of the function is right 10 units.

The rule of the translation is equal to

(x,y) -----> (x-10,y)

so

we have

f(x)=5x+60 ----> function Part A

The new function will be

f(x)=5(x-10)+60

f(x)=5x+10

The graph in the attached figure N 2

The translation of the function right 10 units means that the initial deposit is equal to $10

Part C)

1. Look at the translations, what characteristic of the graph stayed the same in each translation?

In each translation, the slope is the same

The slope m is equal to m=5  

Are parallel lines

2. Look at the original graph and the graph of the translation right 10 units. What vertical translation of the graph in Part B would put the graph back to its original position?

we have

f(x)=5x+10

The vertical translation would be up 40 units

The rule of the translation is equal to

(x,y) -----> (x,y+40)

so

The new function will be

f(x)=5x+10+40

f(x)=5x+50

3 0
4 years ago
Please help urgent!!! i have attached a picture of the question
rusak2 [61]
The length of EH would be 4.8
5 0
4 years ago
Read 2 more answers
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