Answer: (C) 0.1591
Step-by-step explanation:
Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with


Let x be the random variable that represents the lifetime of the tires .
z-score : 
For x= 44,500 miles

For x= 48,000 miles

Using the standard normal distribution table , we have
The p-value : 

Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles = 0.1591
The answer is only I and II
Answer:
coinciding
Step-by-step explanation:
If you divide the second equation by 3, you get the first equation. They describe the same line, so the lines are <em>coinciding</em>.
For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.