The answer is -7
The arrows both point toward the left side, and sine there are seven spaces the arrows are going through, you subtract 7 spaces and get -7
Hope that helps.
Answer: (22) $9,075 (23) $656.25 (24) $217.13
<u>Step-by-step explanation:</u>
Cost Function: C(x) = 5.75x + 8,000
C(10,000) = 5.75(10,000) + 8,000
= 57,500 + 8,000
= 65,500
Revenue Function: R(x) = 9.50x
R(7,850) = 9.50(7,850)
= 74,575
Profit Function: P(x) = R(x) - C(x)
= 74,575 - 65,500
= 9,075
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Retail = Unit Cost + Unit Cost × Markup
= $375 + $375 × .75
= $375 + $281.25
= $656.25
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$225 but if paid within 10 days there is a 3.5% discount
Discount = $225 - $225 × .035
= $225 - $7.88
= $217.13
54 I believe if this is what I think it is the end of the world as we see it the most hardest math riddle to have ever existed 61-47 = 14
47+7=54 54+7= 61 therefore the world as we know shall come to a end at 2:08 PM Central time
Step-by-step explanation:
(a) dP/dt = kP (1 − P/L)
L is the carrying capacity (20 billion = 20,000 million).
Since P₀ is small compared to L, we can approximate the initial rate as:
(dP/dt)₀ ≈ kP₀
Using the maximum birth rate and death rate, the initial growth rate is 40 mil/year − 20 mil/year = 20 mil/year.
20 = k (6,100)
k = 1/305
dP/dt = 1/305 P (1 − (P/20,000))
(b) P(t) = 20,000 / (1 + Ce^(-t/305))
6,100 = 20,000 / (1 + C)
C = 2.279
P(t) = 20,000 / (1 + 2.279e^(-t/305))
P(10) = 20,000 / (1 + 2.279e^(-10/305))
P(10) = 6240 million
P(10) = 6.24 billion
This is less than the actual population of 6.9 billion.
(c) P(100) = 20,000 / (1 + 2.279e^(-100/305))
P(100) = 7570 million = 7.57 billion
P(600) = 20,000 / (1 + 2.279e^(-600/305))
P(600) = 15170 million = 15.17 billion
