All categories

3 years ago

HELP PLS ILL MARK BRAINLIST!!

Mathematics

2 answers:

scoundrel [369]3 years ago

5 0

Answer:

C- $1.70

Step-by-step explanation:

First, put the numbers in order from least to greatest. You then need to separate the numbers in the middle. The middle numbers are 1.65 and 1.75.

You then need to find the number that is in between 1.65 and 1.75 that is common and stays the same. The middle number would be 1.70, so that's your answer.

Naddik [55]3 years ago

4 0

Answer:

D.) $1.74

Step-by-step explanation:

Add up all the prices and then divide by 6 to find the median

= 1.743333333

I hope this helps you! :)

-KeairaDickson

You might be interested in

If m < apd =109 and m <1=17 then m<bpd=

just olya [345]

$m < bpd = 349$

4 0

3 years ago

Which expression is equivalent to (3x^2+4x-7)(x-2)

poizon [28]

Answer:

B. (3x^2+4x-7)+2(3x^2+4x-7) Is your answer

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Unit 9 lesson 2 correlation and best fitting lines

Fittoniya [83]

Answer:

Sorry, I am not quite sure what the question is.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=p%5E%7B2%7Dxp%5E%7B2%7D" id="TexFormula1" title="p^{2}xp^{2}" alt="p^{2}xp^{2}" align="absmidd

vichka [17]

Answer:

${p}^{4} x$

Step-by-step explanation:

1) Regroup terms.

${p}^{2} p^{2} x$

2) Use product rule.

${p}^{2 + 2} x$

3) Simplify 2 × 2 to 4.

$p ^{4} x$

Therefor, the answer is p⁴x

5 0

3 years ago

Read 2 more answers

How do you solve this equation: -2m+3=|15+m|

Elden [556K]

Any number inside the modulus sign becomes positive. This means $|15+m|=|-(15+m)|=|-15-m|$ and so we have,

$-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right$

Solving these gives us

$-2m+3=15+m \Rightarrow m=-4$

$-2m+3=-15-m \Rightarrow = m=18$

However if we check the second solution in the original equation we obtain $-2(18)+3=|15+18| \Rightarrow -33=33$ . This is false and so $m=18$ can't be a solution.

Therefore the only solution is $m=-4$ .

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0

3 years ago