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laila [671]
2 years ago
11

approximately 30,400 citizens of a country died in automobile accident in 2015. express this toll in deaths per day

Mathematics
1 answer:
sertanlavr [38]2 years ago
6 0
If you divide 30,400 by the amount of days in a year 365 you should get 83.3 but because you cant have part of a person lets leave it at 83 death per day
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Each month, Molly budgets $1450 for fixed expenses, $600 for living expenses, and $340 for annual expenses. Her annual net incom
den301095 [7]

Answer:

surplus of 150$

Step-by-step explanation:

1853.68 + 178.  times .249  = ......................owed at the end of the month

1450 +600 + 340 = $2390. * 12=  $28 680. annually ..

30480 - 28680 = $1800. surplus at the end of the year  divided by 12 =  $150.00 monthly surplus

4 0
2 years ago
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Find the volume of the given shape. Round your answer to the nearest<br> hundredth if necessary
xz_007 [3.2K]

Answer:

volume of sphere =4/3πr^3=4/3*22/7*6*6*6=905.14m^3

4 0
3 years ago
Substitute 10 for z in z -5 &lt; 7
EleoNora [17]
Then it would be 10-5 < 7
so if you solved it it would be 5 < 7
So this statement is true
4 0
2 years ago
What is the value of a? -2(a-8)+6a=36
Aleksandr [31]
First we expand the brackets:

-2a + 8 + 6a = 36
4a + 8 = 36

We then need to get the a's onto one side and the numbers onto the other:

4a = 28

We can then divide to get an x by itself:

a = 28/4 = 7
6 0
2 years ago
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$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
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