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3 years ago

approximately 30,400 citizens of a country died in automobile accident in 2015. express this toll in deaths per day

1 answer:

6 0

If you divide 30,400 by the amount of days in a year 365 you should get 83.3 but because you cant have part of a person lets leave it at 83 death per day

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Are these all correct?

sladkih [1.3K]

Problem 1) Line n is the line of symmetry (not line o) because we can fold the lower half to match up with the upper half. The folding line is over line n.

Problem 2) I agree. Nice work on getting the correct answer. The folding line is a vertical line through the center

Problem 3) It's hard to say for sure, but I think the top left corner is NOT reflective over any line of symmetry no matter how you rotate it. So I would uncheck that box. I agree with your other choices though. Great job with those.

4 0

3 years ago

Can someone plz help me with this one problem plzzzzz <br><br> (I’M MARKING BRAINLIEST)

Andre45 [30]

In order from top to bottom, 2,8,14,20
And it’s the second graph (right)

5 0

3 years ago

NEED HELP ASAP!!!!!!

Montano1993 [528]

Answer:

I'm pretty sure its 2.9 hours

Step-by-step explanation:

hope this helps

3 0

2 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

4(y+8)=100 help me pls due today

Otrada [13]

Answer:

y=17

Step-by-step explanation:4(y+8)=100

We move all terms to the left:

4(y+8)-(100)=0

We multiply parentheses

4y+32-100=0

We add all the numbers together, and all the variables

4y-68=0

We move all terms containing y to the left, all other terms to the right

4y=68

y=68/4

y=17

8 0

3 years ago

Read 2 more answers