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3 years ago

approximately 30,400 citizens of a country died in automobile accident in 2015. express this toll in deaths per day

1 answer:

6 0

If you divide 30,400 by the amount of days in a year 365 you should get 83.3 but because you cant have part of a person lets leave it at 83 death per day

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Monica’s retirement party cost two dollars, plus an additional three dollars for every guess she invites. If there are 16 guests

lesya692 [45]

Answer:

TWO BUCKS?? ballin on a budget

anyways, if there are 16 guests, the party would cost $50. sounds a lot more correct lol

8 0

3 years ago

Dave has 15$ to spend on an 8$ book and two birthday cards (cl for his friends. how much can he spend on each card if he buys th

vova2212 [387]

X=15

(X-8)/2

Does that work?

6 0

4 years ago

You noticed that $750 was stolen from your checking account using your debit card, but life being as busy as it is, you didn't r

Mekhanik [1.2K]

Answer:

The answer is: full liability for unauthorized debit charges

Explanation:

Once you discover that an amount of money was stolen from your debit card account, it is important to report it immediately to the card issuer. This will prevent "liability for unauthorized debit charges on your end." Each type of card that you avail has a set of rules when it comes to the card owner's duties and liabilities.

You have to tell your card issuer, either by writing or by phone. This should be done within 60 days from the time you encountered the issue. This will allow you to dispute any unauthorized charges. However, the sooner you report, the better it will be so you won't incur any liabilities.

So, in the case above, you didn't report the fraudulent activity until 75 days. This gives you a "full liability for unauthorized debit charges."

Thus, this explains the answer.

3 0

3 years ago

Someone please help me I’m really lost

docker41 [41]

I think it would be the last one 36

7 0

3 years ago

If lim x-> infinity ((x^2)/(x+1)-ax-b)=0 find the value of a and b

MAXImum [283]

We have

$\dfrac{x^2}{x+1}=\dfrac{(x+1)^2-2(x+1)+1}{x+1}=(x+1)-2+\dfrac1{x+1}=x-1+\dfrac1{x+1}$

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-ax-b\right)=\lim_{x\to\infty}\left(x-1+\frac1{x+1}-ax-b\right)=0$

The rational term vanishes as x gets arbitrarily large, so we can ignore that term, leaving us with

$\displaystyle\lim_{x\to\infty}\left((1-a)x-(1+b)\right)=0$

and this happens if a = 1 and b = -1.

To confirm, we have

$\displaystyle\lim_{x\to\infty}\left(\frac{x^2}{x+1}-x+1\right)=\lim_{x\to\infty}\frac{x^2-(x-1)(x+1)}{x+1}=\lim_{x\to\infty}\frac1{x+1}=0$

as required.

3 0

3 years ago