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12345 [234]
3 years ago
11

Wilton drives a taxicab. He charges $40 per hour. On Tuesday, Wilton earned $30 in tips while driving customers around for the d

ay. (a) What is the unknown information in the scenario? How will you represent this in a math expression?
If you give a vaild answer and Show your work i'll give you brainiest and Best answer.
Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0
It is not known how many hours were worked or the total

t=40h+30

t= total
h= hours
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When the polynomial 4x^4 − 13x^2 − 2x is divided by the polynomial x − 2 , x-2, what is the remainder?
zhenek [66]
Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
3 0
3 years ago
Omar went to the football game. He paid $13.50 for admission. He bought a program for $4.75, a bag of popcorn for $3.50, and a l
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$25.10 is the answer
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2 years ago
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You have 8 cups of flour. A recipe calls for 2/3cup of flour. Another recipe calls for 1/4 cup of flour. How much flour do you h
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There will be 5 more because 8-2-1 =5
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3 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

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2 years ago
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