6(x+5)² + 5(x+5)-4 = 0
(x+5)(x+5) = x(x+5)+5(x+5) = x² + 5x + 5x + 25 = x² + 10x + 25
6(x²+10x+25) + 5(x+5) - 4 = 0
6x² + 60x + 150 + 5x + 25 - 4 = 0
6x² + 60x + 5x + 150 + 25 - 4 = 0
6x² + 65x + 171 = 0
<span>u = (x + 5)</span>
Answer:
The answer to your question is the chocolates are slightly lighter than the weight stated on the label.
Step-by-step explanation:
Data
The label says 0.384 pounds
Actual mass = 0.3798 pounds
Process
To solve this problem the only thing we must do is substrate the actual weight of chocolates to the weight of chocolates stated on the label.
If the result is positive, then the chocolates are lighter
If the result is negative, then the chocolates are heavier
0.384 pounds - 0.3798 pounds = 0.0042
hmu if you need sumin els!
Options A and D are correct. The pair of measurements that could be the dimensions of rectangle B is 6 cm by 1.5 cm and 18 cm by 4.5 cm.
For us to get a scale copy of the dimension, we need to first find the scale factor as shown;
Given the measure of rectangle A:
To get all of the measurement pairs that could be the dimensions of Rectangle B, we need to multiply the length and width by the same factor
Multiplying by 1/2
New length = 12 × 0.5 = 6cm
New width = 3 × 0.5 = 1.5cm
Hence 6cm by 1.5cm can be dimension of B
Multiplying by 1.5
New length = 12 × 1.5 = 18cm
New width = 3 × 1.5 = 4.5cm
Hence 18cm by 4.5cm can be dimension of B
Learn more here: brainly.com/question/24759485
Answer:
12.5%
Step-by-step explanation:
