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IRINA_888 [86]
3 years ago
8

Please be quick!

Mathematics
1 answer:
diamong [38]3 years ago
4 0

Answer:

The value of x is 6

Step-by-step explanation:

Here, we want to calculate the length of the mid-segment

Mathematically;

if we add the length of the two parallel bases and divide by 2, we get the length of the mid-segment

Thus;

(x + 8 + 5x + 4)/2 = 24

6x + 12 = 2(24)

6x + 12 = 48

6x = 48-12

6x = 36

x = 36/6

x = 6

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Answer:

x^2-3x=4

x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

3 0
3 years ago
.<br> The angle measures of a triangle are shown in the diagram.<br> What is the value of x?
vodka [1.7K]

Answer:

ok the second one the answer is 66

Step-by-step explanation:

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6 0
3 years ago
A plane traveled 2565 miles with the wind in 4.5 hours and 2205 miles against the wind in the same amount of time. Find the spee
kherson [118]

Answer:

  • plane: 530 mi/h
  • wind: 40 mi/h

Step-by-step explanation:

Let p and w represent the speeds of the plane and the wind. The relation between time, speed, and distance is ...

  speed = distance/time

  p +w = (2565 mi)/(4.5 h) = 570 mi/h

  p -w = (2205 mi)/(4.5 h) = 490 mi/h

Adding these speeds, we get ...

  (p +w) +(p -w) = (570) +(490) mi/h

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Then the speed of the wind is ...

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7 0
2 years ago
What is an equation of the that passes through the point (-2,-8) and has a slope of 3?
san4es73 [151]
Slope of 3 mean y=3x
to find the equation we say y=3x+C then sub -2 for x and -8 for y to find the C
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so equation would be: y= 3x-2
6 0
3 years ago
Read 2 more answers
Given the following observed and expected data (total of 1000), using chi-squared calculate a p-value that corresponds with this
finlep [7]

Answer:

The answer is "0.90>p>0.75."

Step-by-step explanation:

\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \  -6 36 \ \ \ \ \ \ \ \ \ \ \  0.092308\\\\

roof \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  408 \ \ \ \ \ \ \ \ \ \ \  390  \ \ \ \ \ \ \ \ \ \ \  18 \ \ \ \ \ \ \ \ \ \ \  324  \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \  70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \  49 \ \ \ \ \ \ \ \ \ \ \  0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72  \ \ \ \ \ \ \ \ \ \ \  70  \ \ \ \ \ \ \ \ \ \ \ 2  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \  0.057143\\\\

vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \  \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.257143\\\\

\text{Cinnabar roof} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  -1 \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \  1  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.028571\\\\\text{roof vestigial}  \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.2\\\\

\text{cinnabar}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.8 \\\\

Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1000 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ 2.965934

Eight phenotypes were present.  

Df is provided also by a number of phenotypes -1 The degree of freedom

\to df = 8-1= 7

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

7 0
3 years ago
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