All categories

2 years ago

First down, a football team lost 16 yd. After two

Mathematics

1 answer:

Vikentia [17]2 years ago

8 0

Answer: +21

Step-by-step explanation:

Based on the information given, we are informed that at first down, a football team lost 16 yd and they after two downs, the team had an overall gain of 5 yd.

The number of yards that were gained on second down can be represented by x. We can then form the question as an equation as:

x - 16 = 5

x = 5 + 16

x = 21

The team gained 21 yards.

You might be interested in

Consider the two exponential equations shown. Identify the attributes for each equation to complete the table.

SIZIF [17.4K]

Answer:

$y = 2 5 0 ( 0 . 8 9 ) ^ x$

Initial value: 250

Decay

Decay rate: 11%

$y = 4 0 ( 1.11 ) ^ x$

Initial value: 40

Growth

Growth rate: 11%

Step-by-step explanation:

The function we have on the left of the table is:

$y = 2 5 0 ( 0 . 8 9 ) ^ x$

Initial value (when x = 0): $y = 2 5 0 ( 0 . 8 9 ) ^ 0$

y = 250 (initial value)

Growth or Decay: 0.89 < 1 so decay

Decay rate: (1 - 0.89) * 100 = 11%

Function on right side:

$y = 4 0 ( 1.11 ) ^ x$

Initial value (when x = 0): $y = 4 0 ( 1 . 1 1 ) ^ 0$

y = 40 (initial value)

Growth or decay: 1.11 > 1 so growth

Growth rate: (1.11 - 1) * 100 = 11%

8 0

3 years ago

Read 2 more answers

2) 3x + 4y = 8 2x+y=42 a) (30, -19) b) (31, -20) c) (32,-22) What is the answer

kirza4 [7]

Answer:

Step-by-step explanation:

We can solve simultaneous equations using substitution method, elimination method or graphical method. But for this purpose, we will be using the elimination method.

3x+4y=8 Equation 1

2x+y=42 Equation 2

Multiply Equation 1 by 2 and equation 2 by 3, so as to get the same coefficient for x

2(3x+4y=8)= 6x+8y=16 Equation 3

3(2x+y=42)= 6x+3y=126 Equation 4

Subtract equation 4 from 3, to eliminate x

6x-6x=0

8y-3y= 5y

16-126= -110

We now have 5y=-110

Divide both sides by 5,

y= -110/5

= -22

Substituting for y in equation 2

2x+(-22)= 42

2x= 42+22

2x=64

x= 64/2

= 32

(x, y)

(32, -22)

7 0

3 years ago

Find the area of trapezoid JKLM. Round the answer to the nearest tenth.

maksim [4K]

from the diagram, we can see that the height or line perpendicular to the parallel sides is 8.5.

likewise we can see that the parallel sides or "bases" are 24.3 and 9.7, so

$\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=8.5\\ a=24.3\\ b=9.7 \end{cases}\implies \begin{array}{llll} A=\cfrac{8.5(24.3+9.7)}{2}\\\\ A=\cfrac{8.5(34)}{2}\implies A=144.5~in^2 \end{array}$