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Sergio039 [100]
3 years ago
5

Are the two Rectangles congruent? How do you know?

Mathematics
1 answer:
Veronika [31]3 years ago
5 0

Yes each side and each angle has a congruent corresponding part

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A certain windshield wiper is 10 inches long. The rubber blade is 6 inches long and attached at the outside end. If the wiper sw
Sloan [31]
Area of sector=fraction of sector times area of circle
fraction of sector=degrees/360
and area of circle=pir^2

so
hold  a sec, we have the wiper on the outside, so we want to find the outside ring thing
do
area big sector-area small sector
or even better
(degrees/360) times (area big-areasmall)
big is 10
small is  4 (10-6=4)
areabig=10^2 times pi or 100pi
areasmall=4^2 times pi or 16pi
areabig-areasmall=100pi-16pi=84pi

then find the fraction

84pi times (150/360)=35pi square inches
4 0
3 years ago
-3(z-8)+10=-5<br> What is z equal to?
Brut [27]

Answer:The value of z can be calculated by doing thefollowing steps;

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
What is the value of x in the equation 4x+8y=40 when y = 0.8
fgiga [73]

When y=0.8

4x +8(0.8) =40

-> 4x +6.4 =40

-> 4x = 33.4

-> x=33.4/4

-> x=8.35

Hope it helps...

Regards;

Leukonov/Olegion.

8 0
3 years ago
singh works at a restaurant where he is paid by the hour plus time and a half for his hours over 40. last week he worked four ho
padilas [110]

Answer:

$8.5 per hour

Step-by-step explanation:

Number of overtime hours = 4 hours

Since overtime starts after 40 hours, then the number of hours worked = 40 + 4 = 44 hours

Total amount earned = $391

Let Hourly pay = x

Overtime pay = 1 1/2x = 3/2x

Therefore ;

40x + (4*3/2x) = 391

40x + 6x = 391

46x = 391

x = 391 / 46

x = 8.5

Hourly pay = $8.5 per hour

7 0
3 years ago
A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul
N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula -5t^2+40t+45.

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

(-\frac{b}{2a}, f(-\frac{b}{2a}))

So, let's identify our coefficients. The standard quadratic form is:

ax^2+bx+c

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

x=\frac{-(40)}{2(-5)}

Multiply and reduce. So:

x=-40/-10=4

Now, substitute 4 for t to find the height. So:

-5(4)^2+40(4)+45

Evaluate:

=-5(16)+40(4)+45

Multiply and add:

=-80+160+45=125\text{ meters}

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

-5t^2+40t+45=0

First, let's divide everything by -5. This yields:

t^2-8t-9=0

We can factor:

(t+1)(t-9)=0

Zero Product Property:

t+1=0\text{ or } t-9=0

Solve for t:

t=-1\text{ or } t=9

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

6 0
4 years ago
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