Since you have y alone on one side of the equation......
Use substitution and plug in 1/2x-4 for y in the other equation.

Distribute

Combine like terms

Add 8 to both sides

Divide by 4
and 
Plug this value in for x

Simplify

Multiply everything by 8 and simplify

Divide.....

Your answers are:

4x + 4
This is because there are four sides of a square, and each side is x + 1.
x + 1 + x + 1 + x +1 + x + 1 = 4x + 4
At the end of Round 3, David's score would be 2000.
Answer: 155
Step-by-step explanation:
$300-$85-$60= $155
Answer: 3
Step-by-step explanation:
Let say x the width of the tank,
x+4 its length,
x+2 its height

<u>width=3</u>
length=3+4=7
height=3+2=5