2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Since, it is given that the pentagon ABCDE is congruent to pentagon FGHIJ.
By being congruent, the corresponding angles and sides are equal.
Therefore,
,
,
,
,
.
By using 
So, 
Therefore, the measure of angle 1 is 100 degrees.
So, Option B is the correct answer.

<em><u>Solution:</u></em>
Given that,

We have to find whether the above function is odd or even
If a function is: y = f(x)
If f(-x) = f(x), the function is even
If f(-x) = - f(x), the function is odd
Which is,

From given,

Replace x with -x

Therefore,

Thus the function g(x) is even