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Rzqust [24]
3 years ago
15

Use the quadratic formula to solve the equation.

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

\large\boxed{x=\dfrac{5-\sqrt5}{4},\ x=\dfrac{5+\sqrt5}{4}}

Step-by-step explanation:

\text{The quadratic formula for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac

\text{We have the equation:}\ 4x^2-10x+5=0\\\\a=4,\ b=-10,\ c=5\\\\b^2-4ac=(-10)^2-4(4)(5)=100-80=20>0\\\\x=\dfrac{-(-10)\pm\sqrt{20}}{2(4)}=\dfrac{10\pm\sqrt{4\cdot5}}{8}=\dfrac{10\pm\sqrt4\cdot\sqrt5}{8}=\dfrac{10\pm2\sqrt5}{8}\\\\=\dfrac{2(5\pm\sqrt5)}{8}=\dfrac{5\pm\sqrt5}{4}

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Q12.
SVEN [57.7K]

Answer:

Step-by-step explanation:

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-----------------------

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6 0
3 years ago
Please help ASAP. I am confused
Lesechka [4]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Is the sequence 1, 5, 9, 13, 17, 21, ... arithmetic? If so, find the<br> common difference. /(5 pts)
VikaD [51]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
a rectangular laboratory has a length equal to one and a half times its width and a perimeter of 40m. find its length and width
tresset_1 [31]
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8 0
2 years ago
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Fiesta28 [93]

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Step-by-step explanation:

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