Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
Answer:
Explanation:
A. False - A symporter system requires that one of the molecules to be transported using passive transport.
B. True - The Na+ will move down the established concentration gradient releasing energy to facilitate movement of sucrose against its concentration gradient. This is known as secondary active transport.
C. False - sucrose moves through ion channels not by diffusion to better control its movement across the membrane.
D. True - Movement of molecules against their concentration gradient thus requiring energy input is known as active transport.
E. False - One of the molecules needs to be moving against its concentration gradient.
F. False - A Uniporter system allows the binding and transport of a single molecule at a time. A symporter allows simultaneous binding and transport of Na+ and sucrose molecules.
<span>d. subsistence strategy.</span>
Answer: The correct option is b (false).
Explanation: As is is cleared from the figure that when lactose is absent, the lac repressor binds tightly to the operator. It gets in RNA polymerase's way and prevent transcription.
Answer: it was necessary to see data from more plants before the conclusion could be accepted
Explanation: i got it right
