Express 5n+2 - 51+1 – 5" inthe simplest form.

Mathematics

1 answer:

saw5 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

5n-53

Hope it helps

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Between 1989 and 1998, the population of smalltown, USA ( in thousands) can be modeled by f(x)=.24x^2 -0.96x + 4, where x=0 repr

maks197457 [2]

Just use derivatives:

f'(x)= .48x-.96 = 0, x = 2, since the coeff of x^2 is +, this is a minimum

x=0 1989, so x = 2 is 1991! :)

8 0

3 years ago

Can y’all help me pleaseeee

Lapatulllka [165]

It would be x to the 1/4. Just like how the square root of x is to the power 1/2. Its just something you have to remember that the root is the denominator and the power under the radical is the numerator

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3 years ago

Melissa and alondra shared $72 in the ratio of 3:5. What is melissas share if the money? What is alondras share of the money

Lunna [17]

3:5

3+5 =8

72/8 = 9

9*3 = 27

9*5 =45

Melissa had $27

Alondra had $45

7 0

3 years ago

What is the slope of this line?

Brums [2.3K]

Answer:

$slope=\frac{1}{4}$

Step-by-step explanation:

The slope of a line can be seen as:

$\frac{rise}{run}$

Rise over run is the change in the y values over the change in x values. For example, in this graph, you would start on one of the points given. From there, you would move up first. After moving up a certain number of spaces, you would move to the side until you reach the other point.

In the graph, you would move up until you are in line with one of the other points. Starting at (-4,5), move up one space, then to the left 4 spaces to reach the point (0,6). Using the spaces moved in the rise over run:

$\frac{1}{4} =\frac{rise}{run}=slope$

Therefore, the slope is $\frac{1}{4}$ .

This is true for any two points on the line.

:Done

*When you move up, the number will be positive $(\frac{+y}{x} )$ . If you move down, the number will be negative $(\frac{-y}{x} )$ . If you move left, the number will be positive $(\frac{y}{+x})$ . If you move right, the number will be negative $(\frac{y}{-x} )$ . Keep this in mind. It is very important.