For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:

Answer:
h(f(x)) = 2x - 11
(the second answer is f(h(x)) = 2x - 4)
Step-by-step explanation:
h(x-7) = 2(x-7) + 3
h(x) = 2x -14 + 3
h(x) = 2x - 11
He has -269 dollars available, symbolizing he is in debt.
Answer:
The second graph near the bottom with a Y-intercept of -1
Answer:
yes jess does have enough for her sandbox
Step-by-step explanation:
I did this test to and jess does indeed have enough for the sandbox