1230 1203 1302 1320 1032 1023 2130 2103 2301 2310 2032 2023 3210 etc
The answer is d.61. 66+7=73. 13+8=21. 52+9=61. 10+10=20
Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So






Rounding up:
A sample size of 1031 is required.
I assume you need to solve for g?
12g + 6 = 78
- 6
12g = 72
÷ 12
g = 6
I hope this helps! Let me know if you want me to explain anything :)
Answer:
-2g-12
Step-by-step explanation: