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Valentin [98]
3 years ago
9

If

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

5 + 2i

Step-by-step explanation:

We were given the complex numbers;

a =  - 2 - 5i

and

b =  - i

We want to find the product;

a {b}^{3}

We substitute the complex numbers into the expression and simplify:

( - 2 - 5i)( {i)}^{3}

This is rewritten as:

( - 2 - 5i)( {i)}^{2}  \times i

Note that

{i}^{2}  =  - 1

We substitute to obtain:

( - 2 - 5i)  \times - iLet us expand to get:

- 2 \times  - i + 5i \times  - i

This simplifies to:

2i - 5 {i}^{2}

This gives:

2i - 5( - 1) = 2i + 5

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Negative four and one third ÷ two and one fifth
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The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33

<h3>Fraction division</h3>

negative four and one third ÷ two and one fifth

-4 1/3 ÷ 2 1/5

= -13/3 ÷ 11/5

  • Multiply by the reciprocal of 11/5

  • The reciprocal of 11/5 is 5/11

= -13/3 × 5/11

= (-13 × 5) / (3 × 11)

= -65 / 33

= -1 32/33

Therefore, the solution to the fraction is -1 32/33

Learn more about fraction:

brainly.com/question/11562149

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artcher [175]
The answer would be twelve 12 because 6x.5 is 3 and 3+9 is equal to 12
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3 years ago
Write 9.68 x 104 in standard form?
-Dominant- [34]

Answer:

1006.72

Step-by-step explanation:

Multiply 9.68 by 104

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Lester orders a book for $35. He must pay a shipping charge of 12%. Show how to find 12% of $35 by using benchmark percents, the
Elis [28]

Answer:

$4.2

Step-by-step explanation:

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2. 0.12 of $35 = 0.12 × $35

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For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.

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