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Valentin [98]
3 years ago
9

If

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

5 + 2i

Step-by-step explanation:

We were given the complex numbers;

a =  - 2 - 5i

and

b =  - i

We want to find the product;

a {b}^{3}

We substitute the complex numbers into the expression and simplify:

( - 2 - 5i)( {i)}^{3}

This is rewritten as:

( - 2 - 5i)( {i)}^{2}  \times i

Note that

{i}^{2}  =  - 1

We substitute to obtain:

( - 2 - 5i)  \times - iLet us expand to get:

- 2 \times  - i + 5i \times  - i

This simplifies to:

2i - 5 {i}^{2}

This gives:

2i - 5( - 1) = 2i + 5

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ipn [44]

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

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3 years ago
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PSYCHO15rus [73]

Answer:

c

Step-by-step explanation:

segment BD has an "equidistant" distance and very similar to the distance between points C and E.

As we can see from the graph, point C is located between segment BD and point D is located in the middle of segment CE; and since the points are Equidistant (at the same distance), and both have a point in the middle, it can be deduced that their distances are equal or similar

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What is t²=81. thanks!!
seraphim [82]

Answer:

t= 9, t= -9

Step-by-step explanation:

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Lubov Fominskaja [6]
The answer is 6 17/100
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