Answer:
Acceleration= final velocity - initial velocity / time
= (15 - 0)/ 5
= 3 m/s^2
Force = mass X acceleration
= 2 X 10^3 X 3
= 6 X 10^3 N
-70560, -9.8/2 = -4.9
120^2 = 14400.
Now you multiply 14400 * -4.9 = -70560m.
Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated;
= 150 MW
Heat input;
= 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input;
- Net power generated; 
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s
The farther the distance, the weaker the gravitational force