If this were to happen then the particle would be at the node (the point in the middle where the lines meet). Therefore, the particle will not move up or down because you can see the waves interfere destructively so there is no movement at the node.
answer. The particle will remain stationary due to interference.
Answer:
To your left
Explanation:
The direction of the force exerted on charged particle due to a magnetic field is given by the right-hand-rule, where:
- The index finger indicates the direction of motion of the electron
- the middle finger gives the direction of the magnetic field
- the thumb gives the direction of the force if the particle is positively charged - otherwise, the direction is reversed
in this case, we have an electron (so, a negatively charged particle):
- The direction of motion (index finger) is horizontal, toward you
- The electron begins to curve upward as it enters the field, so this means that the force exerted on the electrons is upward --> the thumb must point downward (because the electron is negatively charged)
- The index finger gives us the direction of the magnetic field: therefore, to your left.
D wavelength
velocity deals w/ speed
frequency/amplitude deals with sound
Answer:
A )
Explanation:
This change in frequency observation occur due to doppler effect
if the wave source moves,In the time between one wave peak being emitted and the next, the source will have moved so that the shells will no longer be concentric. The wavefronts will get closer together in front of the source as it travels and will be further apart behind it. (see the graph)
when the person standing still in front of the ambulance, he will observe a <em>higher frequency </em>than before as the source travels towards them.
The pitch we hear depends on the frequency of the sound wave.
A high frequency corresponds to a high pitch
as we hear a higher frequency , it makes the <em>pitch higher</em> too
Answer:
25.71 kgm/s
Explanation:
Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.
Given that K₂ = 0.7K₁
1/2mv₂² = 0.7(1/2mv₁²)
v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s
Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.
Th magnitude of object A's momentum change is thus 25.71 kgm/s
