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dsp73
3 years ago
9

How many elements did mendeleev place in group 2​

Physics
1 answer:
Pepsi [2]3 years ago
8 0

Answer:5

Explanation:

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A fire hose has an inside diameter of 6.40 cm. Suppose such a hose carries a flow of 40.0 L/s starting at a gauge pressure of 1.
inessss [21]

Answer:

The Reynolds numbers for flow in the fire hose.

Explanation:

Given that,

Diameter = 6.40 cm

Rate of flow = 40.0 L/s

Pressure P=1.62\times10^{6}\ N/m^2

We need to calculate the Reynolds numbers for flow in the fire hose

Using formula of rate of flow

Q=Av

v=\dfrac{Q}{A}

Where, Q = rate of flow

A = area of cross section

Put the value into the formula

v=\dfrac{40.0\times10^{-3}}{3.14\times(3.2\times10^{-2})^2}

v=12.44\ m/s

We need to calculate the Reynolds number

Using formula of the Reynolds number

n_{R}=\dfrac{2\rho\times v\times r}{\eta}

Where, \eta =viscosity of fluid

\rho =density of fluid

Put the value into the formula

n_{R}=\dfrac{2\times100\times12.44\times3.2\times10^{-2}}{1.002\times10^{-3}}

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3 years ago
A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s. Assuming the diameter of a tire is 58.0 cm, (a)
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Answer:

Explanation:

Given:

Initial velocity, u = 0 m/s (at rest)

Final velocity, v = 22 m/s

Time, t = 9 s

Diameter, d = 58 cm

Radius, r = 0.29 m

Using equation of motion,

v = u + at

a = (22 - 0)/9

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Theta = 99.02/0.29

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1 rev = 360°

341.44°,

= 341.44/360

= 0.948 rev

= 0.95 rev

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