(a) Determine the circumference of the Earth through the equation,
C = 2πr
Substituting the known values,
C = 2π(1.50 x 10¹¹ m)
C = 9.424 x 10¹¹ m
Then, divide the answer by time which is given to a year which is equal to 31536000 s.
orbital speed = (9.424 x 10¹¹ m)/31536000 s
orbital speed = 29883.307 m/s
Hence, the orbital speed of the Earth is ~29883.307 m/s.
(b) The mass of the sun is ~1.9891 x 10³⁰ kg.
Transverse waves. Direction of vibration of the particles is at right angles to direction of movement.
Answer:
<h3>The answer is 2.51 s</h3>
Explanation:
The time taken can be found by using the formula
d is the distance
v is the velocity
From the question we have
We have the final answer as
<h3>2.51 s</h3>
Hope this helps you
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