the wavelength is to be 56.67 cm and I know that i should be applying the double slit equation for destructive interference.
Answer:
The Reynolds numbers for flow in the fire hose.
Explanation:
Given that,
Diameter = 6.40 cm
Rate of flow = 40.0 L/s
Pressure 
We need to calculate the Reynolds numbers for flow in the fire hose
Using formula of rate of flow


Where, Q = rate of flow
A = area of cross section
Put the value into the formula


We need to calculate the Reynolds number
Using formula of the Reynolds number

Where,
=viscosity of fluid
=density of fluid
Put the value into the formula


Hence, The Reynolds numbers for flow in the fire hose.
Answer:
Explanation:
Given:
Initial velocity, u = 0 m/s (at rest)
Final velocity, v = 22 m/s
Time, t = 9 s
Diameter, d = 58 cm
Radius, r = 0.29 m
Using equation of motion,
v = u + at
a = (22 - 0)/9
= 2.44 m/s^2
v^2 = u^2 + 2a × S
S = (22^2 - 0^2)/2 × 2.44
= 99.02 m
S = r × theta
Theta = 99.02/0.29
= 341.44 °
1 rev = 360°
341.44°,
= 341.44/360
= 0.948 rev
= 0.95 rev
B.
Final angular speed, wf = v/r
= 22/0.29
= 75.86 rad/s