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Serga [27]
3 years ago
13

What is the magnitude of the net force acting on a 2.0 x10^3 kilogram car?

Physics
1 answer:
Tatiana [17]3 years ago
7 0
Answer:  
Acceleration= final velocity - initial velocity / time
 = (15 - 0)/ 5
 = 3 m/s^2
 Force = mass X acceleration
 = 2 X 10^3 X 3
 = 6 X 10^3 N
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Answer: 3 m.

Explanation:

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As we are asked to locate Jack at some distance from the fulcrum, we can take torques regarding the fulcrum, which is located at just in the middle of the length of the seesaw.

If we choose the counterclockwise direction as positive, we can write the torque equation as follows (assuming that Jill sits at the left end of the seesaw):

mJill* 5m -mJack* d = 0

60 kg*5 m -100 kg* d =0

Solving for d:

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6 0
3 years ago
A spring with constant k = 78 N/m is at the base of a frictionless, 30.0°-inclined plane. A 0.50-kg block is pressed against the
olasank [31]

Explanation:

The given data is as follows.

   Spring constant (k) = 78 N/m,     \theta = 30^{o}

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According to the formula of energy conservation,

                mgh sin \theta = \frac{1}{2}kx^{2}

       h = \frac{1}{2} \times \frac{kx^{2}}{mg Sin \theta}

          = \frac{78 \times 0.04}{2 \times 0.5 \times 9.8 \times 0.5}

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Thus, we can conclude that the distance traveled by the block is 0.64 m.

4 0
3 years ago
A5.0 kg TNT explosive, initially at rest, explodes into two pieces. One of the pieces weighing 2.0 kg flies off to
nordsb [41]

Answer:

v = 24 m/s, rightwards

Explanation:

Given that,

The mass of TBT explosive = 5 kg

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The law of conservation of momentum holds here. Let v be the final speed of the remaining piece. So,

5\times 0=2\times (-36)+3\times v\\\\-72=-3v\\\\v=24\ m/s

So, the final speed of the remaining piece is 24 m/s and it is in the right direction.

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3 years ago
Consider a spherical capacitor with radius of the inner conducting sphere a and the outer shell b. The outer shell is grounded (
AleksAgata [21]

Answer:

Explanation:

The application of Gauss's law is used in the derivation as shown with detailed step by step in the attached file.

The potential difference on this spherical capacitor is ΔV = Va - Vb = kQ/a - kQ/b = kQ(1/a - 1/b)

6 0
4 years ago
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N76 [4]
D
Step-by-step explanation:
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4 years ago
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