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marysya [2.9K]
3 years ago
6

Please help!!!! Find X and Y

Mathematics
1 answer:
Rudik [331]3 years ago
5 0

Answer: X=15 , Y=15\sqrt{3}

Step-by-step explanation:

This triangle is a 30, 60, 90 so that means it would be - a, 2a, a\sqrt{3} on each side, so add that all together and you get x-15 and y-15\sqrt{3}

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Quadrilateral PQRS is inscribed in a circle , as shown. Which statement is true?
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Two sides of a right triangle have the lengths 4 and 5. What is the product of the possible lengths of the third side? Express t
marishachu [46]

Answer:

19.2

Step-by-step explanation:

<u>1st Case:</u>

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

<u>2nd Case</u>

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

x^2=9

x=3

<u>Final Step</u>

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

Anwser: <u>19.2</u>

6 0
3 years ago
Plzzzzz help ASAP!!!!!! Solve: x/32=15/20
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The product of the extremes, (x)(20),

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So we have (x)(20) or 20x equals (32)(15) or 480.

So we have 20x = 480.

Dividing both sides by 20, <em>x = 24</em>.

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3 years ago
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