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Nastasia [14]
3 years ago
11

How do you do this? Find M

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

Step-by-step explanation:

Let angle ABZ be angle 1 and angle ZBC be angle 2.

Angle 1 = 85 degree

Angle 2 = 6x + 9

measure of angle ABC = 24x+4

Angle 2 = ABC - 85

6x + 9 = 24x + 4 - 85

6x - 24x = 4 - 85 - 9

-18x = -90

x = -90/-18 = 90/18 =

x = 5

Therefore the measure of angle 2 = 6*5 + 9 = 30+9 = 39 degree

Therefore the measure of angle ZBC = 39 degree

Hope you understand

Please mark as brainliest

Thank You

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29 plus x Equals 90 im a lil smart so ntm
solniwko [45]

29 + x = 90 \\ x = 61

5 0
3 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

8 0
2 years ago
1/9(-9x+18)-1/5(10+15x)
garri49 [273]

Answer:

-4x

Step-by-step explanation:

5 0
3 years ago
What is 33% of 420 round to the nearest hundredth
LUCKY_DIMON [66]

Answer:

138.6

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
If m<1=40 and m<2=80, what is m<3?
prohojiy [21]

Answer:

60 degrees, 55 degrees, and 50 degrees respectively

Step-by-step explanation:

Equation: m<1+m<2+m<3=180

1. 40+80+x=180 Subtract 120(because 40+80=120)

  x=60

2. 50+75+x=180 subtract 125 (50+75=125)

    x=55

3. 50+80+x=180 subtract 130 (50+80=130)

   x=50

5 0
3 years ago
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