A money box contains only 10-cent and 20-cent coins. There are 34 coins with a total value of $5.40. How many coins of each
1 answer:
10x+20y=540
x+y=34
y=34-x
Plug in (34-x) for y:
10x+20(34-x)=540
10x+680-20x=540
-10x=-140
10x=140
x=14
There were 14 ten cent coins and 20 20 cent coins
You might be interested in
1/2 plus 1/3 is 5/6.
You have to find the common denominator
Answer:
F. right angle is correct
Try this:
V=a³=6.2³=238,328 in.³
Answer: A.
Answer:
11 units
Step-by-step explanation:
Just trust me!
