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Shtirlitz [24]
3 years ago
12

A money box contains only 10-cent and 20-cent coins. There are 34 coins with a total value of $5.40. How many coins of each

Mathematics
1 answer:
kow [346]3 years ago
4 0
10x+20y=540
x+y=34
y=34-x

Plug in (34-x) for y:
10x+20(34-x)=540
10x+680-20x=540
-10x=-140
10x=140
x=14

There were 14 ten cent coins and 20 20 cent coins
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Answer:

\sqrt{13}

Step-by-step explanation:

We are given an isosceles triangle. We need to remember the important rule that the base angles are equal. In this question we need to find the value of 'x' using a perpendicular height of 3 and a base length of 4. In this question we can half the triangle in half to help us find the value of x. Also we need to use Pythagoras theorem to help us find 'x'. Pythagoras states that a² + b² = c² so we want to find the hypotenuse of the triangle. If we half the triangle we get 2 triangle both with a base length of 2 and a perpendicular height of 3 so,

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→ 13 = c²

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→\sqrt{13}  =  c

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