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zimovet [89]
3 years ago
15

Can somebody help me on this and if so please answer correctly​

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
4 0
The answer is A. Good luck man!! :)
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Solve by factoring the equation x^2+36=12x
Fudgin [204]
x^2+36=12x\\\\x^2-12x+36=0\\\\x^2-6x-6x+36=0\\\\x(x-6)-6(x-6)=0\\\\(x-6)(x-6)=0\\\\(x-6)^2=0\iff x-6=0\Rightarrow\boxed{x=6}
6 0
3 years ago
Any one know the answer it has to be turned in tomorrow morning
Veseljchak [2.6K]
17: 900 because 3,000 + 900 + 40 +7 is 3,947 or 3,947-3,000-40-7= 900
6 0
3 years ago
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What is the simplest form for 30/42? thanks!?
andre [41]
It would be: 30/42 = 15/21 = 5/7

In short, Your Answer would be 5/7

Hope this helps!
7 0
3 years ago
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Josh volunteered at the zoo for 14 hours in one month. This was 3 1/2 times as many hours as Gina volunteered. How many hours di
jonny [76]
This one you can't really make a formula for or anything, but it's fairly simple to figure out, with a bit of guess and check.
14 is really close to 15, but that's bigger, so let's try a smaller number that would work.
It has to be divisible by 2, because you've got a whole number that is 3 1/2 times the other number. (1/2 of a whole number means it's divisible by 2).
10 is divisible by 2,
10 ÷ 2 = 5
But, 10 x 3 = 30 which is much bigger than 14.
So, we've got to start with a smaller number.
Let's try something really small, like 4. We could try 2, but 2 x 3 = 6, which, even with 1/2 of 2, isn't nearly close to 14.
Now, 4 x 3 = 12
That's quite close to 14.
And 1/2 of 4 is 2.
All we do now is add 12 to 2 and see if it works.
12 + 2 = 14
14 = 14
This one works.
That means that Gina volunteered for 4 hours, because 3 1/2 x 4 = 14.
5 0
4 years ago
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Point M is the midpoint of AB. If the coordinates of M are (2,8) and the coordinates of A are (10,12),what are the coordinates o
ElenaW [278]

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{10}~,~\stackrel{y_1}{12})\qquad B(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ x + 10}{2}~~~ ,~~~ \cfrac{ y + 12}{2} \right)~~=~~\stackrel{M}{(2,8)}\implies \begin{cases} \cfrac{x+10}{2}=2\\[1em] x+10=4\\ \boxed{x=-6}\\[-0.5em] \hrulefill\\ \cfrac{y+12}{2}=8\\[1em] y+12=16\\ \boxed{y=4} \end{cases}

4 0
3 years ago
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