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zimovet [89]
2 years ago
15

Can somebody help me on this and if so please answer correctly​

Mathematics
1 answer:
mrs_skeptik [129]2 years ago
4 0
The answer is A. Good luck man!! :)
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Which of these prices is lower than 5 for $9.00? (A). 3 for $6.00. (B). 8 for $16.00. (C). 6 for $10.00. (D). 10 for $19.00
almond37 [142]
A is the answer of the question
7 0
3 years ago
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How to find the legs of a right triangle with only the hypotenuse?
GuDViN [60]

Let x = legs of right triangle.

The set up would be:

x^2 + x^2 = (hypotenuse)^2

Understand?

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2 years ago
Determine the quotient, q(x), and remainder, r(x) when
Fed [463]
ANSWER

Quotient:

q(x) = {x}^{2} - 4x + 7\\

Remainder:

r(x) = 11x - 29

EXPLANATION

The given functions are

f(x) = 4 {x}^{4} + 12 {x}^{3} + 17 {x}^{2} + 19x + 6

and

g(x) = 4 {x}^{2} + 4x + 5

We want to find the quotient and the remainder when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

q(x) = {x}^{2} - 4x + 7

The remainder is

r(x) = 11x - 29

5 0
3 years ago
1. Which store had the highest demand both before and after the price increase?
Anna71 [15]

Answer:

The answer is Store 4

Step-by-step explanation:

As before the price increases, Store 4 has the highest price among other Stores. After price increases, Store 4 continued to has highest price among them

6 0
2 years ago
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A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
2 years ago
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