Question

Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution. x = one fourth, solution is not extraneous x = one fourth, solution is extraneous x = 3, solution is not extraneous x = 3, solution is extraneous

Answer 1

Answer:

x=3, solution is not extraneous

Step-by-step explanation:

we have

$\sqrt{8x+1}=5$

Solve for x

squared both sides

$(\sqrt{8x+1})^2=5^2$

$8x+1=25\\8x=25-1\\8x=24\\x=3$

Verify

For x=3

$\sqrt{8(3)+1}=5$

$\sqrt{24+1}=5$

$\sqrt{25}=5$

$5=5$ -----> is true

therefore

x=3, solution is not extraneous