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Dovator [93]
3 years ago
10

Given the equation square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution. x = one fourth, solut

ion is not extraneous x = one fourth, solution is extraneous x = 3, solution is not extraneous x = 3, solution is extraneous
Mathematics
1 answer:
Rainbow [258]3 years ago
5 0

Answer:

x=3, solution is not extraneous

Step-by-step explanation:

we have

\sqrt{8x+1}=5

Solve for x

squared both sides

(\sqrt{8x+1})^2=5^2

8x+1=25\\8x=25-1\\8x=24\\x=3

<u><em>Verify</em></u>

For x=3

\sqrt{8(3)+1}=5

\sqrt{24+1}=5

\sqrt{25}=5

5=5 -----> is true

therefore

x=3, solution is not extraneous

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Answer:

The answer to your question is below

Step-by-step explanation:

Data

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