Answer:
Z=2.36
P=0.0091
Step-by-step explanation:
The hypothesis is:
π > 0.55 which is the population proportion
The formula to get the test statistic is
Zstat = P-π/√π(1-π)/n
P =507.4/860 = 0.59 (sample proportion )
n =860 (sample size)
π =0.55(population porportion)
Zstat = 0.59-0.55/√0.55(1-0.55)/860
Zstat =2.36
From Z table the probability of Z score of 2.36 is 0.9909
To calculate for P- value will then be
P= 1 - 0.9909
P= 0.0091
Answer:
0.13591.
Step-by-step explanation:
We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.
We know that z-score tells us that a data point is how many standard deviation above or below mean.
To solve our given problem, we need to find area between z-score of -2 and -1 that is 
.
We will use formula 
to solve our given problem.
Using normal distribution table, we will get:
Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.
Answer:
it is 8
Step-by-step explanation:
because EG is E+G which is 8+3 which equals 11 so it is 8
Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
