Question

Hellppp plzzzz ??...........

Answer 1

Answer:

B. $\dfrac{3\sqrt{2}}{2}$

Step-by-step explanation:

The sides forming the right angle are called the legs. Since the two angles shown are congruent, the legs are congruent.

We can use the Pythagorean theorem.

$a^2 + b^2 = c^2$

$x^2 + x^2 = 3^2$

$2x^2 = 9$

$x^2 = \dfrac{9}{2}$

$x = \sqrt{\dfrac{9}{2}}$

$x = \dfrac{3}{\sqrt{2}}$

$x = \dfrac{3}{\sqrt{2}} \times \dfrac{\sqrt{2}}{\sqrt{2}}$

$x = \dfrac{3\sqrt{2}}{\sqrt{2}\sqrt{2}}$

$x = \dfrac{3\sqrt{2}}{2}$