N.B. I believe your question is saying that the price of a cup of coffee was $2.40 yesterday, and it rose to $2.65 today. Therefore, I will solve with these prices.
The percent increase is 10.41666666% (The 6 is repeating.).
First, you find the difference, or increase, between the two prices.
New price - Old price = Increase
$2.65 - $2.40 = $0.25
The difference between the two prices is $0.25. To find the percent increase, you want to divide the original price ($2.40) from the increase ($0.25) and multiply by 100.
Increase ÷ Original Price × 100 = % increase
0.25 ÷ 2.40 × 100 = 10.41666666%
The percent increase is 10.41666666% (The 6 is repeating.).
X = D/(1 - h)
1 - h = D/x
h = 1 - D/x
D = 400, X = 4000
h = 1 - 400/4000
h = 1 - 0.1 = 0.9
Answer: the term number is 38
Step-by-step explanation:
Let the number of the term be x
The value of the xth term = 488
In an arithmetic sequence, the terms differ by a common difference, d. This means that the difference between two consecutive terms, d is constant.
The formula for the nth term is
Tn = a + (n-1)d
Where
Tn = the nth term of the arithmetic sequence
a = the first term of the arithmetic sequence.
d = common difference.
From the information given,
a = 7
d = 13
We are looking for the xth term.
Tx = 488 = 7 + (x-1)13
488 = 7 + 13x - 13
Collecting like terms on the left hand side and right hand side of the equation,
13x = 488 -7 + 13
13x = 494
x = 38
The value of the 38th term is 488.
It will be 1/6 because it one side out of 6 tries
Answer:
Step-by-step explanation:
<u>Implicit Differentiation</u>
We use implicit differentiation when it's not possible to find an expression of y as a function of x, or the expression is very hard to differentiate.
The implicit differentiation takes the original equation and differentiates each term, usually applying the product, quotient, power, or other similar rules.
In the course of the differentiation, we'll use f' as the derivative of f.
We'll find y'=dy/dx in the following equation:
Differentiating:
The derivative of a constant is 0, thus:
The first term is a product of variables, so we apply the product rule:
The second term is the power of y. We apply the chain rule:
![[f(g)]'=f'.g'](https://tex.z-dn.net/?f=%5Bf%28g%29%5D%27%3Df%27.g%27)
Operating:
Since x'=1:
Subtracting 3y:
Take y' as a common factor:
Solve for y':
