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Crazy boy [7]
3 years ago
8

The procedure known as determines which digit at the right of the number will be the last digit displayed and increases it by on

e if the next digit
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
This procedure is known as estimating or rounding, where one compares the digit to the right is the number and sees whether or not is found within a given range, greater than 5 and can be used to increase the number in question, by a value of 1.
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if there's a 1/3 chance that it will rain today, what fraction represents the chance that it will not rain
marissa [1.9K]

Answer:

2/3 i think

Step-by-step explanation:

4 0
3 years ago
Around 2.232 to the nearest hundredth
Korolek [52]

2.232\approx2.32

3 0
3 years ago
Sam makes some bread rolls. He gives 2/5 of the bread to his neighbor and 4/9 of the remainder to his cousin. He has 15 tools le
Cerrena [4.2K]

Answer:

Sam initially made 45 bread rolls

Step-by-step explanation:

Let x = total number of bread rolls made by Sam. He gives 2/5 of the bread to his neighbor. This means he gave 2/5 × x =

2x/5 bread rolls to his neighbor.

The remainder would be x - 2x/5 =3x/5

He gave 4/9 of the remainder to his cousin = 4/9 ×3x/5=12x/45

=4x/15

He has 15 bread rolls left

Total number of bread rolls = what he has left + what he gave his cousin + what he gave his neighbor

x = 15 + 4x/15 + 2x/5

Taking LCM of 15 and cross multiplying

15x= 225+4x + 6x

15x = 225 +10x

15x-10x = 225

5x = 225

x = 225/5 =45

Sam initially made 45 bread rolls

4 0
4 years ago
Find the point, M, that divides segment AB into a ratio of 5:2 if A is at (1, 2) and B is at (8, 16).
d1i1m1o1n [39]
Since M divides segment AB into a ratio of 5:2, we can say that M is 5/(5+2) of the length of AB. Therefore 5/7 × AB.
distance of AB = d
5/7×(x2 - x1) for the x and 5/7×(y2 - y1) for the y
5/7×(8 - 1) = 5/7 (7) = 5 for the x
and 5/7×(16 - 2) = 5/7 (14) = 10 for the y
But remember the line AB starts at A (1, 2),
so add 1 to the x: 5+1 = 6
and add 2 to the y: 10+2 = 12
Therefore the point M lies exactly at...
A) (6, 12)


4 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
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