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Anna71 [15]
3 years ago
8

The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.Wha

t is the smallest possible perimeter of the triangle, rounded to the nearest hundredth?
Mathematics
1 answer:
Art [367]3 years ago
6 0
Let "x" be the  longest side and "y" be each of <span>remaining sides
If the triangle is </span>аcute<span> then:

</span>y² + y² > x² <span>
2y</span>² > 30²
2y² > 900
y² > 450
<span>y > </span>√450
y > 21.21 ← <span>to the nearest hundredth
</span>
This means the length of each of the remaining sides is not less than 21.22 in  (to the nearest hundredth), so <span>the smallest possible perimeter of the triangle =
30 + 21.22 + 21.22 = 72.44 in.

</span><span>
</span>
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<u>Step-by-step explanation</u>:

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Hope this is helpful to you!
  Best wishes!
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