Let "x" be the longest side and "y" be each of <span>remaining sides If the triangle is </span>аcute<span> then:
</span>y² + y² > x² <span> 2y</span>² > 30² 2y² > 900 y² > 450 <span>y > </span>√450 y > 21.21 ← <span>to the nearest hundredth </span> This means the length of each of the remaining sides is not less than 21.22 in (to the nearest hundredth), so <span>the smallest possible perimeter of the triangle = 30 + 21.22 + 21.22 = 72.44 in.
