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Marrrta [24]
3 years ago
11

Homework help, one of the few I have

Mathematics
2 answers:
Alex73 [517]3 years ago
8 0

Answer:

x=4 and the solution is not extraneous

Step-by-step explanation:

\sqrt{2x+1}=3 \\\\2x+1=9 \\\\2x=8 \\\\x=4

This solution is not extraneous, because plugging it back in you get:

\sqrt{2(4)+1}=3 \\\\\sqrt{9}=3 \\\\3=3

Hope this helps!

Bogdan [553]3 years ago
7 0

Answer:

X = 4, solution is not extraneous

Step-by-step explanation:

3 = √9

so we get the following comparison;

2X + 1 = 9 (both minus 1)

2X = 8 (divide by 2)

X = 4

if we fill in 4 for X. we get

√2•4+ 1 = √9 = 3 so the solution is not extraneous

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Furkat [3]

Answer:

<em>x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)</em>

Step-by-step explanation:

<u>Equations</u>

The situation can be written as an algebraic equation by setting the variables as follows:

x = first integer

x + 1 = second integer

x + 2 = third integer

x + 3 = fourth integer

x + 4 = fifth integer

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The sum of all six numbers must be equal to 7 times the second number, thus:

x + x + 1 + x + 2 + x + 3 + x + 4 + x + 5 + x + 6 = 7(x + 1)

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3 years ago
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zubka84 [21]

Answer:

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5 0
3 years ago
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notka56 [123]

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Step-by-step explanation:

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