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3 years ago

Subtract. −4.9 (1.3) Enter your answer in the box as a fraction in simplest form..

1 answer:

8 0

Make -4.9 into a fraction by making the 4 the whole number the 9 the numerator and 10 the denominator because 9 is in the tenths place then do the same thing to 1.3 change the 1 to the whole number then make the 3 the numerator and make 10 the denominator. Then subtract the two fractions and then simplify

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8n = -3m + 1; n = -2, 2, 4

bogdanovich [222]

I am assuming you want to solve for m in each case

8n = -3m + 1

8(-2) = -3m + 1

-16 = -3m + 1

-3m = -17

m = $\frac{17}{3}$

8(2) = -3m + 1

16 = -3m + 1

-3m = 15

m = -5

8(4) = -3m + 1

32 = -3m + 1

-3m = 31

m = $\frac{31}{3}$

8 0

3 years ago

Read 2 more answers

Every five years in March, the Population of a certain town is recorded. In 1995, the town had a population of 4,500 people. Fro

alexgriva [62]

4,500 plus 15% is 5,175 minus 4% is 4,968 so your answer is 4,968.

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3 years ago

Kevin needs 1,000 ribbons for a school event. Each ribbon has to be 2.25 feet long. Tell how Kevin can use a pattern to find how

marysya [2.9K]

2.25 x 1000 = 2250.

That's how much yds of ribbons he needs.

7 0

3 years ago

X = -2y + 300 3y = 800 - 4x

devlian [24]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x=-2y+300&(1)\\3y=800-4x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\3y=800-4(-2y+300)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3y=800+(-4)(-2y)+(-4)(300)\\\\3y=800+8y-1200\\\\3y=8y-400\qquad\text{subtract}\ 8y\ \text{from both sides}\\\\-5y=-400\qquad\text{divide both sides by (-5)}\\\\y=80\\\\\text{Put it to (1):}\\\\x=-2(80)+300\\\\x=-160+300\\\\x=140$

8 0

3 years ago

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Please help :0 i have a bad grade and desperately need to bring it up

murzikaleks [220]

Answer: y=1.5x+5 slope 1.5

explanation: it the first two questions

7 0

2 years ago

Subtract. ​ −4.9 (1.3) Enter your answer in the box as a fraction in simplest form..

Subtract. −4.9 (1.3) Enter your answer in the box as a fraction in simplest form..