The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer: 19t +100
Step-by-step explanation:
19t +100 where t is the number of hours she worked and the extra 100 dollars is the money she got from her friend.
Answer:
Numbers of packs p is 12
Step-by-step explanation:
Data :
Money = $18
Price of a card = $1.5
Equation : 18 ≥ 1.5p
Solve the equation for p
18/1.5 ≥ p
12 ≥ p
Answer:
I would say 6:12.
Step-by-step explanation:
it is equivalent to 12:24 because 12/2= 6 and 24/2 = 12 so 6:12 is your answer!