For this problem, you know that the first walker will arrive 2 hours before the second, and increases his speed by 2 times the second walker. You also know there is a distance of 24 km. So up until some time x, the two walkers have to be going the same speed. If the first walker increases speed by two times the speed per hour, and arrives two hours earlier, then his initial speed will be 20 km/h, because after 2 hours, he will have an increase of 4 km/hr, and the second will have an increase of 2 km/h, thereby making the first arrive 2 hours earlier, if that makes sense.

5 0

4 years ago

Tap A fills a tank in 4hours while B fills the same tank in 3hours. Tap C empties this tank when full in 2hours. If the tank is

boyakko [2]

Answer:

<em>It will take 12 hours to fill the tank</em>

Step-by-step explanation:

Proportions

Tap A fills a tank in 4 hours. It means each hour it fills 1/4 of the tank.

Tap B fills the tank in 3 hours. Each hour it fills 1/3 of the tank.

Tap C empties the tank when full in 2 hours. Each hour it empties 1/2 of the tank.

Each hour, the tank gets filled by:

$\displaystyle \frac{1}{4}+\frac{1}{3}-\frac{1}{2}=\displaystyle \frac{3}{12}+\frac{4}{12}-\frac{6}{12}=\frac{3+4-6}{12}=\frac{1}{12}$

Since the tank fills 1/12 of its capacity in one hour, it follows that it will take 12 hours to fill the tank

6 0

3 years ago