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nika2105 [10]
3 years ago
15

In un trapezio rettangolo la base minore, il lato obliquo e l'altezza misurano rispettivamente 60 cm. 95 cm è 76 cm. Calcola il

perimetro e l'area del trapezio. THANKS
Mathematics
1 answer:
KengaRu [80]3 years ago
8 0

Answer:

2p=348 cm\: S=6726 cm^{2}

Step-by-step explanation:

Ciao, come stai?

1) Per prima cosa, dobbiamo trovare la misura della base più grande. Scomponendo la figura possiamo visualizzare un triangolo e un quadrato. Ci sono somiglianze con gli angoli. Quindi è un triangolo rettangolo. Applichiamo il teorema di Pitagora:

a^2=b^2+c^2\\95^2=b^2+76^2\\57=b

2) Perimetro:

2p=60+57+76+60+95\\2p=348 cm

3) L' area

\frac{(B+b)h}{2} =\frac{(117+60)76}{2} =6726 \:cm^{2}

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<em>Keywords: system of equations, elimination method, substitution method, graphing method</em>

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