Question

Find f(t-3) for f(×)=4x^2-8×+4

Answer 1

Answer:

4t^2-32t+64=4(t^2-8x+16)

Step-by-step explanation:

f(x)=4x^2-8x+4

f(t-3)=4(t-3)^2 - 8(t-3)+4=

4(t^2-2*t*3+9)-8t+24+4=

4(t^2-6t+9)-8t+28=

4t^2-24t+36-8t+28=

4t^2-32t+64=4(t^2-8x+16)