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Studentka2010 [4]
4 years ago
5

Find f(t-3) for f(×)=4x^2-8×+4

Mathematics
1 answer:
Ivan4 years ago
3 0

Answer:

4t^2-32t+64=4(t^2-8x+16)

Step-by-step explanation:

f(x)=4x^2-8x+4

f(t-3)=4(t-3)^2 - 8(t-3)+4=

4(t^2-2*t*3+9)-8t+24+4=

4(t^2-6t+9)-8t+28=

4t^2-24t+36-8t+28=

4t^2-32t+64=4(t^2-8x+16)

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20 : 100% = x : 115%

Step-by-step explanation:

Do 115 x 20

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8 0
3 years ago
the perimeter of the circular base of a cone is 132 cm and its vertical height is 28 cm find the curved surface area total surfa
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Answer:

i. Curved surface area = 2310 cm^{2}

ii. Total surface area = 3696 cm^{2}

iii. volume = 12936 cm^{3}

Step-by-step explanation:

Perimeter of the circular base = circumference of the circle = 132 cm

circumference of a circle = 2\pir

132 = 2\pir

r = \frac{132}{2\pi }

 = \frac{66}{\pi }

r = 66 x \frac{7}{22}

 = 3 x 7

 = 21

radius = 21 cm

vertical height, h = 28 cm

Thus applying the Pythagoras theorem,

l^{2} = h^{2} + r^{2}

  = 28^{2} + 21^{2}

  = 784 + 441

  = 1225

l = \sqrt{1225}

l = 35 cm

The slant height is 35 cm.

i. Curved surface area = \pirl

                           = \frac{22}{7} x 21 x 35

                           = 22 x 3 x 35

                           = 2310

curved surface area of the cone is 2310 cm^{2}.

ii. Total surface area = \pi r^{2} + \pirl

                                  = \pir(r + l)

                                  = \frac{22}{7} x 21 (21 + 35)

                                  = 22 x 3 x 56

                                  = 3696

The total surface area of the cone is 3696 cm^{2}.

iii. volume of a cone = \frac{1}{3}\pi r^{2}h

                                  =  \frac{1}{3} x \frac{22}{7} x 21^{2} x 28

                                   = 12936

The volume of the cone is 12936 cm^{3}

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