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2 years ago

5

If a football field is 100 yards long and 54 yard wide and what is the area in perimeter of that football filed

1 answer:

OlgaM077 [116]2 years ago

7 0

Answer:

5400

Step-by-step explanation:

you would measure the length and width. Multiply the length by the width to get the area, and add twice the length to twice the width to get the perimeter

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The lengths of the sides of a triangle are in a the extended ratio of 3:6:8. The triangles perimeter is 510cm. What are the leng

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I think
(Total)
3 : 6 : 8 = 17
(Times by 30 to get total then you times by each ratio/side)

90 : 180 : 240= 510cm

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2 years ago

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3 years ago

F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.

Rom4ik [11]

Answer:

$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

$17.~g(f(-5))=\Large\boxed{1}$

$18.~f(g(-5))=\Large\boxed{-3}$

Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

$f(7)=(7)+4$

$f(7)=\Large\boxed{11}$

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

<u />

<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

$g(6.5)=2(6.5)+3$

$g(6.5)=13+3$

$g(6.5)=\Large\boxed{16}$

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

1 year ago

Ms. Turner drove 825 miles in March. She drove 3 times as many miles in March as she did in January. She drove 4 times as many m

navik [9.2K]

825/3 = 275 which is how many miles she drove in January.

275*4= 1100 which is how many miles she drove in February.

Ms. Turner drove 1100 miles in February.

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3 years ago

What is the domain of the function on the graph

Butoxors [25]

All real numbers greater than or equal to -3

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3 years ago

Read 2 more answers