Inaccurate and misleading
Answer:
Comparison.
Explanation:
When we have to find a largest in a list of n elements.First we have to iterate over the list so we can access all the elements of the list in one go.Then to find the largest element in the list we have to initialize a variable outside the loop with the minimum value possible and in the loop compare each element with this value,if the element is greater than the variable assign the element to the variable.Then the loop will find the largest element and it will be the variable.
Answer:
<u>720</u> possible PIN can be generated.
Explanation:
To calculate different number of orders of digits to create password and PIN, we calculate permutation.
Permutation is a term that means the number of methods or ways in which different numbers, alphabets, characters and objects can arranged or organized. To calculate the permutation following formula will be used:
nPr = n!/(n-r)!
there P is permutation, n is number of digits that need to be organize, r is the size of subset (Number of digits a password contains)
So in question we need to calculate
P=?
where
n= 10 (0-9 means total 10 digits)
r= 3 (PIN Consist of three digits)
So by using formula
10P3 = 10!/(10-3)!
=10!/7!
= 10x9x8x7!/7!
= 10x9x8
= 720
favorite_color = input("Enter favorite color:\n")
pet = input("Enter pet's name:\n")
num = input("Enter a number:\n")
print("You entered: "+favorite_color+" "+pet+" "+num)
password1 = favorite_color+"_"+pet
password2 = num+favorite_color+num
print("First password: "+password1)
print("Second password: "+password2)
print("Number of characters in "+password1+": "+str(len(password1)))
print("Number of characters in "+password2+": "+str(len(password2)))
This works for me.
