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vaieri [72.5K]
4 years ago
6

Find the length of LM: K 16 L M

Mathematics
1 answer:
Tanzania [10]4 years ago
8 0

Answer:

8

Step-by-step explanation:

LM = KI/2

LM = 16/2

LM = 8

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Describe the transformation<br> that moves ABC to its image<br> A'B'C'.
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All it did was it counter clock wise rotated to make the shape look like it’s a mirror
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3 years ago
Ishaan is 3 times as old as Christopher and is also 14 years older than Christopher.
aniked [119]
<span>The correct answer is: 21

Explanation:
Let's first assume few variables!

x = Ishann's age (in years)
y = Christopher's age (in years)

1. Ishann is 3 times as old as Christopher can be represented mathematically as:
x = 3y ---- (1)

2. Ishann is 14 years older than Christopher can be represented mathematically as:
x = y + 14 ---- (2)

Get the value of y from Equation (1) and plug it in Equation (2):

(2) => x = (x/3) + 14
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Hence Ishann is 21 years old!</span>
3 0
3 years ago
Read 2 more answers
Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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Step-by-step explanation:

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3 years ago
Find the surface area of a sphere<br> with a radius of 9 cm.<br> Surface Area = [?] cm?
miskamm [114]

Answer:

1,017.36  \:  {cm}^{2}

Step-by-step explanation:

Surface area of a sphere

= 4\pi {r}^{2}  \\  = 4 \times 3.14 {(6)}^{2}  \\  =  12.56 \times 81 \\  = 1,017.36  \:  {cm}^{2}

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3 years ago
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