Let Jean's speed while running = x mph
Then Jean's speed while riding will be = x+9 mph
Distance covered by running = 8 miles
Distance covered by riding = 11 miles
Total time taken to complete the race = 1.5 hours
As, 
So, time for running= 
And time for riding= 
Equation becomes:

Now, multiply every term by 2x(x+9) to clear denominators:

Simplifying it we get

Solve the quadratic equation using formula

putting a=3 , b= -11, c= -144
we get (x - 9)(3x + 16) = 0
where x=9 and x=
Neglect the negative answer as speed cannot be negative, so x = 9 mph
Hence, Jean's running speed is 9 mph and riding speed is x+9 = 9+9 = 18 mph
Answer:


Step-by-step explanation:
Given

Required
Solve:

Open bracket

Take LCM



Take LCM


Divide by 3/3

Step-by-step explanation:
It's telling you to plug in the numbers inside the parenthesis as x
Example: F(-1)= 2(-1)^3 -3(-1)^2 +7
Answer:
Make sure you convert these numbers into one unit. Convert everything to yard. Just convert the feet and inches in yard since it's the biggest unit, and then add them together. You should get a fraction not a whole number.