Answer:
The expected number of contracts the sales representative will get this week is 5.22
Step-by-step explanation:
For each client, there are only two possible outcomes. Either there is a sales contract, or there is not. The probability of having a sale contract with each client is independent of other clients. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

In this problem, we have that:

What is the expected number of contracts the sales representative will get this week?

The expected number of contracts the sales representative will get this week is 5.22
Answer:
2, and 5
Step-by-step explanation:
. V = B( h )
. V = (pi) (r squared) (h)
Answer:
2/3 give 3 with a g(8) 25 real
Since your probably solving for W, isolate W by adding the -3n to both sides and get W=5n now use a calculator and multiply 5 and Pi. To Get 15.7.
I used N for pi since I don’t have that symbol
You need to specify what needs to be solved so I just assumed W
Answer:
15
Step-by-step explanation:
100 laps
100 divided by 20 Is 5
3 x 5 is 15
please brainliest me