9514 1404 393
Answer:
78.5 km
Step-by-step explanation:
Measured at the airport, the angle between the two planes is ...
180° -60° -50° = 70°
The law of cosines tells us the distance between the planes is ...
d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km
The planes are about 78.5 km apart.
1st piece = x
2nd piece = x+2
3rd piece = x+2+3 = x+5
37 = x +x+2 + x+5 =
37 = 3x+7
30=3x
x = 30/3 = 10
1st piece = 10 inches
2nd piece = 10+2 = 12 inches
3rd piece = 10+5 = 15 inches
1.) <1=25°, <2=155°, <4=155°
1. (5x-8)=(8x-17)
5x-8x=-17+8
-3x=-9
x=3
2. (3x+5) + (4x-7) =180
3x+5+4x-7=180
3x+4x=180-5+7
7x=182
x=26