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alexira [117]
3 years ago
13

Help i don’t know what to do here!

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0

Answer:

Find the are

Step-by-step explanation:

pi method

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30 mins = how many seconds???
horrorfan [7]
6x3=18 add two zeros and you get 1800 seconds:) hope this helped
8 0
3 years ago
Read 2 more answers
Hey i need help this assignment is like 3 pages long
slavikrds [6]

Answer:

c=1.96

Step-by-step explanation:

2.1/c=1.5/1.4

2.1*1.4=1.5*c

2.94/1.5=1.5c/1.5

c=1.96

7 0
3 years ago
I don't know how to find a different angle from this. PLEASE HELP FIND X!!!! THANKS!!!
timama [110]

The intersection of the two red rays forms a set of vertical angle pairs. In such a pair, angles opposite one another have the same measure, so the angle opposite the one labeled 93 degrees also has measure 93 degrees.

The red ray on the right together with the black ray pointing directly to the right form a pair of supplementary angles, whose measures add up to 180 degrees. This means the angle adjacent to the one labeled 128 degrees has measure 180 - 128 degrees.

In any triangle, the interior angles' measures add up to 180 degrees. So we have

? + 93 + (180 - 128) = 180

? + 93 - 128 = 0

? = 128 - 93

? = 35

8 0
3 years ago
Adam bought note pads at a 1.45 each and 10 towels he gave the cashier $100 and received $46 change find the cost of the towel
notsponge [240]
$100-$46 = $54 which is how much was spent. 54-1.45 = 52.55 divide that by 10 and you get 5.25

Each towel was $5.25
4 0
3 years ago
General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
3 years ago
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