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Andre45 [30]
3 years ago
10

What are the exact solutions of x2 + 5x + 1 = 0? (5 points)

Mathematics
1 answer:
Rus_ich [418]3 years ago
7 0

Answer:

x=\frac{-5\pm\sqrt{21}  }{2}

Step-by-step explanation:

We use the quadratic formula here which says for a quadratic equation ax^2+bx+c=0.

x= \frac{-b\pm\sqrt{b^2-4ac} }{2a}

Now in our case

a=1\\b=5\\c=1

so we have:

x=\frac{-5\pm\sqrt{5^2-4(1)(1)}  }{2(1)} =\frac{-5\pm\sqrt{21}  }{2}

\boxed{x=\frac{-5\pm\sqrt{21}  }{2} }

Which are our solutions.

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Lelu [443]
What's the problem? There's no example...
8 0
2 years ago
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
.    |  1   2  -2    0

which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
If 50 one-cent coins were stacked on top of
Sedbober [7]

To make 8 inch tall column approximately 61 coins required.

Given,

Total one cent coins stacked on top of each other in a column = 50

Height of column = 378 inches

Approximate height of one coin = ( 50 / 378)

                                                    = 0.132 inches

To make an 8 inches tall stack No of coins required will be:

Number of coins required  = ( total height / height of one coin )

                   = ( 8 / 0.132 )

                   = 60.60

                    ≅ 61 coins

To make 8 inch tall column approximately 61 coins required.

Learn more about coins here: brainly.com/question/11677207

#SPJ4

7 0
1 year ago
Please help will make the BRAINLIEST 50 points !
melomori [17]

Answer:

you given me only 25 point

7 0
2 years ago
Solve each triangle using the information provided. If necessary, round to the<br> nearest tenth.
Goryan [66]

Answer:

1) B = 66.5° c = 10.9

Step-by-step explanation:

I will do question one as an example. In general, for these questions you want to use the appropriate trigonometric ratios to solve for the variables and/or apply logic using rules regarding triangles. See attached image for all solving steps.

For side c, we can use Cosine of angle A for a ratio between 10 and c. When we write out the equation, we can solve for side c. So when we write it out, we get the equation:

cos23.5 = ¹⁰⁄c

c = ¹⁰⁄cos₂₃.₅

c = 10.9044 (make sure to round to the nearest tenth, which is one decimal place)

For angle B, since they have given two angles, you can solve for B since all angles of a triangle add up to 180 degrees.

So b = 180 - (90 + 23.5) = 180 - 113.5

b = 66.5

  • It is also possible to solve this using sine of angle B and solve it from there, but applying the theory this way is much simpler. (this is on the image if you're curious about it)

I hope this helps you with the other 3 questions.

4 0
3 years ago
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