Question

Solve and graph the absolute value inequality |4x+1|<_5

Answer 1

$|4x+1|\leq5\\ 4x+1\leq5 \wedge 4x+1\geq-5\\ 4x\leq 4 \wedge 4x\geq -6\\ x\leq 1 \wedge x\geq-\dfrac{3}{2}\\ x\in\left \langle -\dfrac{3}{2},1\right\rangle$